Alex De Minaur vs Rei Sakamoto
Alex De Minaur leads the head-to-head 1–0. Last meeting: Shanghai Rolex Masters, 11 Oct 2026, won by Alex De Minaur 7-6(6) 6-4. Data as of 17 Oct 2026.
Alex De Minaur holds the higher overall Elo, 1852 to 1669 for Rei Sakamoto. Recent form, last five tracked matches: Alex De Minaur 3 wins, Rei Sakamoto 3.
Serve and return in their meetings
Across the 1 meeting with full match stats. Aces and double faults are totals over those matches.
| Minaur | Sakamoto | |
|---|---|---|
| 59% | First serve in | 67% |
| 92% | Points won on 1st serve | 71% |
| 62% | Points won on 2nd serve | 58% |
| 33% | Return points won | 20% |
| 100% | Break points converted | 0% |
| 11 | Aces | 13 |
| 2 | Double faults | 0 |
All meetings
- Alex De Minaur won 7-6(6) 6-411 Oct 2026 · Shanghai Rolex Masters · R3 · Hard
Source: our tennis data provider, as of 17 Oct 2026. Matches without a recorded winner (abandoned or unfinished) are not listed.
Player pages: Alex De Minaur · Rei Sakamoto. Today's matches with model and market are on the model board.
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